UNIDAD III.- DERIVADA DE UNA FUNCION

A) Incrementos.- La finalidad de los incrementos es ver el momento en que la recta secante se convierte en tangente, cuando el  D x®0 , a la derecha o a la izquierda.
Análisis Gráfico:                                                                                   y
                                                                                                                               RECTA SECANTE
                                                                                             y2 = f ( x1 )                 
1.-­ Dx  =  x2  -  x1                                                                                   
                                                                                                                                     RECTA TANGENTE
2.- Dy  =  y2  -  y1  =  f ( x2 ) - f ( x1 )                                                  Dy
           
                                                                                              y1 = f ( x2 )                 q      q1


                                                                                                                D x®0                                       x





Ejemplos:

1.- Dada la función  y  =  x2  +  1,  si la variable  x,  se incrementa  de  x1 = 1  a  x2 = 3

Solución:


1.-­ Dx  =  x2  -  x1
            =  3   -   1  =  2 u



2.- Dy  =  y2  -  y1

     Dy  =         f ( x2 )      -      f ( x1 )
                  [ ( 3 ) 2 + 1 ] - [ ( 1 )2 + 1 ]  =   8 u


       



  RECTA SECANTE :

3.-   m  =  Tg q           

       q  = Arc tg  ( 4 ) =  75º 57’49”

4.-  ( y2 - y1 ) = m ( x2 - x1 )     P ( 1,2 )
            y - 2   = m ( x - 1 )     
                  y  =  mx - m + 2    --------  Ec 1
                  y  =  x2 + 1            --------  Ec 2


( MET. DE  IGUALACION )
  mx - m + 2  =  x2 + 1
            x2 + 1 - mx + m - 2 = 0
            x2  - mx +  ( m - 1 ) = 0
            A = 1    B = -m     C = m - 1
            b2 - 4ac = 0
            m2 - 4m + 4 = 0    Þ  ( m - 2 ) 2  \ m = 2
  
       
 RECTA  TANGENTE

5.-      m1  =  Tg q1               2AOP)    dx ( v n ) = n v n -  1
            q1  =  Arc Tg ( 2 )               dx ( x 2 ) = 2x
            q1  =  63º 26`6”                              = 2(1)
                                                                    \     m = 2          




a) Tabulación                          b) Gráfica                                         y                                         RECTA SECANTE
                                                                                                                                 
                                                                                                                                  RECTA  tangente
                                                                                                                         
              x           y                                                                                                   
                                                                             f (x) = x2+1      Dy
            -2           5                                                                            
            -1            2      
             0            1
             1            2                                                                                                   q        q1
             2            5                                         
                                                                                         
                                                                                                              
                                                                                                        0        D x®0                                            x


2.-Dada la función  f (x) = x3 + x , si la variable x se incrementa  de x1  = -1  a  x2 = 2



1.-­ Dx  =  x2  -  x1
            =  2   +  1  = 3 u

2.- Dy  =  y2  -  y1
     Dy  =  f ( x2 )  -  f ( x1 )
            =  12  u

RECTA SECANTE :

3.-   m  =  Tg q m    = Dy   =   12   =   4
                                        Dx         3

       q  = Arc tg  ( 4 ) =  75º 57’49”
RECTA  TANGENTE

4.-   d ( v n )  = n v n -  1
  d ( x 3 + x ) = 3x2+1
   
                       En el  P (0,0)                                              \   m = 1               
      q  = 45º
                                 P (1,2)                                              \   m = 4
      q  =  75º 57’49”              
                                P (2,10)                                              \   m = 13               
      q  =  85º 36’5”
a) Tabulación

      x     y = x3 + x     y
     -2                      -10
     -1                        -2
    -½                 -0.625
      0                          0
     ½                     0.625
     1                          2
     2                        10
           





B)  Análisis  geométrico:
                                  
                                                                      tg q =
                                     f(x)               
  y2
   
           Dy                                                           Lím            Derivada de la función f (x) ”
  y1                                                                  Dx ® 0    
                      Dx
                x1           x2

Geométricamente la derivada de una función es la pendiente de una recta tangente en cualquier punto de su gráfica.
B) Regla de los cuatro pasos

Análisis  gráfico:
                                              
                                                      f ´ (x) = m            f ’(x) =   Lim    Lim    
  y2  = f (x1+h)       f (x)                                                            Dx ® 0                Dx ® 0       
                       
                        Dy
                                                                                  Lím       f ( x1+ h ) - f ( x1 )
  y1  = f (x1)                                                                      h® 0                 h
                                  
                                 Dx = h                                         Generalizando:
                              x1          x2 = x1 + h
                                                                                  f ’(x) =  Lím      f ( x1+ h ) - f ( x1 )
                                                                                               h ® 0                  h


La regla de los cuatro pasos.- Es el método original para calcular la derivada  de una función, se le llama así porque se recomienda calcular el límite del modelo en cuatro pasos; que son los siguientes:

1.-Se realiza la evaluación f ( x + h )

2.-Se efectúa la operación  f ( x + h ) - f ( x )

3.-Se realiza la división   f ( x + h ) - f ( x )
                                                  h
4.-Se calcula f’ (x)  =  Lim     f ( x + h ) - f ( x )
                                   h ® 0                h

Ejemplos:
Calcular la derivada de las función siguientes

1.-  f ( x ) =  2x + 1

1.- f ( x + h )                           = 2 ( x + h ) + 1
2.- f ( x + h ) - f ( x )              = 2x + 2h + 1 - 2x - 1
                                                = 2h
3.- f ( x + h ) - f ( x )              = 2h  = 2
                                        h                                  h
4.- Lim    f ( x + h ) - f ( x )    = Lim ( 2 )  =    f ’ ( x )  = 2
                             h ® 0              h                        h ® 0     

2.-  f ( x ) = 2x2
                                                                       = 2 ( x + h ) 2
                                                                       = 2 ( x2 + 2xh + h2 )
                                                                       = ( 2x2 + 4xh + 2h2 ) - ( 2x2 )
                                                                       = 4xh  +  2h2
                                                                       =  h   ( 4x + 2h )   =  Lim ( 4x + 2h )  =   f ’ ( x )  =  4x
                                                                                  h                    h ® 0


3.-  f ( x )  = 1 - x                                                                                                      \   f ’ ( x )  =  -1
4.-  f ( x )  = 3x - x2                                                                                       \  f ’ ( x )  =  3 - 2x

5.-  f ( x )  = 3x2 - 2x + 3                                                                               \  f ’ ( x )  =  6x - 2

6.- 

1.-                   =       1   
                                                                (x + h )
2.-                   =        1     - 1 =  x - ( x  + h )   =     -h__
                                                                (x + h )   x        x2  + hx           x2  + hx
3.-                   =        -h        =        -1   .         
                                                               h( x2 + hx)       x2  + hx
4.-                   =       -1                                             
                                                    x2 + (0)x                                                                   

7.-                                                                                                                           

8.-                                                                                          


9.-                                 
                        1.-                   = 
                        2.-                   = 
                        3.-                   = 
                        4.-                   =  Lim                     
                                                  h ® 0                              


10.-                                                                                                  

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